If the two equal charges separated with one unit (one meter) has a force of 20 N. What will be the force if the distance is increased by 2 units (two meters)? What is the value of the new force compared to the old?

Answer 1

1 + 2 = 3 m is the final separation

R^2 increases by a factor of 9.

The electrostatic repulsion force decreases by a factor of 9.