Asked by Tia
So is this right for prime factorization
be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ?
be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ?
Answers
Answered by
Anonymous
Looks right to me
Answered by
Tia
Thank you !
Answered by
Steve
not to me. 2 appears twice, so you'd have 2^2 * 2^3 = 2^5
Answered by
Kristin & Tia
What does it multiply too? equal too?
confused now.
How do I write this then ??
"So is this right for prime factorization
be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ? "
confused now.
How do I write this then ??
"So is this right for prime factorization
be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ? "
Answered by
Eric
Statement of notice and recognition of being.
Answered by
Ayanna
2 to the exponent of 3 3 times 5 to the exponent of 2 and times 11
Answered by
Ayanna
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