Asked by Tia
So is this the correct prime factorization
be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ?
which equals ?
be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ?
which equals ?
Answers
Answered by
drwls
What number are you factorizing into primes? Without knowing that, I cannot tell you if your prime factors are correct.
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