Asked by Owen
If a 20 gram sample of a radioactive substance has a half-life of 6000 years, how many grams would be present after 18000 years?
Answers
Answered by
Elena
Radioactive decay law
N =N₀exp(-λt)=
=N₀exp(-ln2•t/T)=
=20exp(-0.693•18000/6000) = 2.5 g
N =N₀exp(-λt)=
=N₀exp(-ln2•t/T)=
=20exp(-0.693•18000/6000) = 2.5 g
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.