Asked by Jane
Jess is running around a circular track, one lap every 40 seconds. Mackenzie is also running at a constant speed around the same track, but in the opposite direction. They meet every 15 seconds. How many seconds does it take Mackenzie to do one lap?
Answers
Answered by
Henry
d1 = (15s/40s) * 1Lap = 15/40=3/8 Lap =
Jess' distance.
d1 + d2 = i Lap.
3/8 + d2 = 1
d2=1 - 3/8 = 5/8 Lap in 15s.=Mackenzie'
distance.
T = 15s/(5/8)Lap = 15 * 8/5 = 24 s/Lap.
= Mackenzie' speed.
Jess' distance.
d1 + d2 = i Lap.
3/8 + d2 = 1
d2=1 - 3/8 = 5/8 Lap in 15s.=Mackenzie'
distance.
T = 15s/(5/8)Lap = 15 * 8/5 = 24 s/Lap.
= Mackenzie' speed.
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