Asked by Ann
Write an equation of a line perpendicular to y=2x+3 and passes through (3,4).
Answers
Answered by
Mac
Slope of the given line is 2 , therefore the slope of the perpendicular line is -(1/2)
Use your point slope equation y -y =m(x - x)
Y - 4 = -(1/2)(x - 3)
2(y - 4) = -1(x - 3). You are looking a proportion and cross multiplying
2y - 8 = -1x + 3
2y. =. -1x + 11
y. = -(1/2)x + (11/2)
Use your point slope equation y -y =m(x - x)
Y - 4 = -(1/2)(x - 3)
2(y - 4) = -1(x - 3). You are looking a proportion and cross multiplying
2y - 8 = -1x + 3
2y. =. -1x + 11
y. = -(1/2)x + (11/2)
Answered by
Reiny
perpendicular to y = 2x + 3 implies the new equation must be
y = (-1/2)x + b
sub in the point (3,4)
4 = (-1/2)(3) + b
b = 4 + 3/2 = 11/2
y = (-1/2)x + 11/2
y = (-1/2)x + b
sub in the point (3,4)
4 = (-1/2)(3) + b
b = 4 + 3/2 = 11/2
y = (-1/2)x + 11/2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.