Question
how do you find out the vertex when graphing inequalities of quadratics in equations like this y<x^2-16
it factors out to like x+4 x-4 and I know that i can use that to find the x intercepts but the way to find the vertex i don't understand
it factors out to like x+4 x-4 and I know that i can use that to find the x intercepts but the way to find the vertex i don't understand