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Mrs. Black has one begonia plant. If she buys two begonia plants each year for every one she has, how many will she have in fou...Asked by Anonymous
Mrs. Black has one begonia plant. If she buys two begonia plants each year for every one she has, how many will she have in four years?
Please explain the answer.
Please explain the answer.
Answers
Answered by
Steve
every year she has 3 times as many plants
1+3+9+27+81 = 121
1+3+9+27+81 = 121
Answered by
bobpursley
first year 1
second year 2+1
third year 6 +2+1
fourth year=18+6+2+1
total= sum above
second year 2+1
third year 6 +2+1
fourth year=18+6+2+1
total= sum above
Answered by
Aasiyah
24 plants
first year 1+2=3
second year 3x2=6
third year 6x2=12
fourth year 12x2=24
first year 1+2=3
second year 3x2=6
third year 6x2=12
fourth year 12x2=24
Answered by
Logan
First year
1+ 2=3
Second year
3+2+2+2=9
Third year 9+2+2+2+2+2+2+2+2+2=27
Fourth year
27+[27•2]=81
1+ 2=3
Second year
3+2+2+2=9
Third year 9+2+2+2+2+2+2+2+2+2=27
Fourth year
27+[27•2]=81
Answered by
Jaynon
You times by three every year:
First year=3
Second year=9
Third year=27
Fourth year=81
First year=3
Second year=9
Third year=27
Fourth year=81
Answered by
H
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