Asked by simran
A Toy is in the form of a hemisphere surmounted by a right circular cone of the same base radius as that of the hemisphere .If the radius of base of the cone is 21 cm and its volume is 2/3 of the volume of hemisphere calculate the height of cine and surface area of the toy.
Answers
Answered by
Reiny
The missing part is the height of the cone, but it is 2/3 the volume of the hemisphere (semi-sphere).
volume of hemisphere = (1/2 (4/3)π (21^3) = 6174π
but the volume of the cone is 2/3 of that or 4116π
vol of cone = (1/3)π r^2 h
4116π = (1/3)π(21^2)h
12348 = 441h
h = 28
Now use your formulas for surface area of a sphere, take half of that , and use your formula for the surface area of a cone with radius 21 and height 28
Make sure NOT to include the circular base joining them when finding surface area
volume of hemisphere = (1/2 (4/3)π (21^3) = 6174π
but the volume of the cone is 2/3 of that or 4116π
vol of cone = (1/3)π r^2 h
4116π = (1/3)π(21^2)h
12348 = 441h
h = 28
Now use your formulas for surface area of a sphere, take half of that , and use your formula for the surface area of a cone with radius 21 and height 28
Make sure NOT to include the circular base joining them when finding surface area
Answered by
Sajitha K
Volume of cone =
3
2
Volume of hemisphere
3
1
πr
2
h=
3
2
(
3
2
πr
3
) ; r =Common radius h = Cone height
h=
3
4
r=
3
4
(21)=28cm
Slant height, l=
r
2
+h
2
=
21
2
+28
2
=35cm
Total surface area = CSA
cone
+CSA
hemisphere
=πrl+2πr
2
=πr(l+2r)=5082cm
2
Solve any question of Surface Areas and Volumes with:-
3
2
Volume of hemisphere
3
1
πr
2
h=
3
2
(
3
2
πr
3
) ; r =Common radius h = Cone height
h=
3
4
r=
3
4
(21)=28cm
Slant height, l=
r
2
+h
2
=
21
2
+28
2
=35cm
Total surface area = CSA
cone
+CSA
hemisphere
=πrl+2πr
2
=πr(l+2r)=5082cm
2
Solve any question of Surface Areas and Volumes with:-
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