Asked by anne
finding the product for (7x+1)(x^2+1) and for the problem (2x+6)(x-10) Also finding the product thank you very much
Answers
Answered by
drwls
It is importnt that you attempt these problems yourself. use the rule that
(a+b)(c+d) = a(c+d) + b(c+d)
=ac + ad + bc + bd.
In other words, add up all the possible pairs of products from each of the two terms in parentheses.
In the first case, the answer is
7x^3 + 7x + x^2 + 1
Now you try the other one.
(a+b)(c+d) = a(c+d) + b(c+d)
=ac + ad + bc + bd.
In other words, add up all the possible pairs of products from each of the two terms in parentheses.
In the first case, the answer is
7x^3 + 7x + x^2 + 1
Now you try the other one.
Answered by
Count Iblis
Use the rule:
X(A + B) = X A + X B
If you take:
X = (7x+1),
A = x^2 and
B = 1,
you get:
(7x+1)(x^2 + 1) = (7x+1)x^2 + (7x+1)1 =
x^2 (7x+1) + 7x+1
You can now expand the term x^2 (7x+1)
by using the same rule again. So you put:
X = x^2,
A = 7 x,
B = 1
X(A + B) = X A + X B
If you take:
X = (7x+1),
A = x^2 and
B = 1,
you get:
(7x+1)(x^2 + 1) = (7x+1)x^2 + (7x+1)1 =
x^2 (7x+1) + 7x+1
You can now expand the term x^2 (7x+1)
by using the same rule again. So you put:
X = x^2,
A = 7 x,
B = 1
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