Asked by simranpreet
find the value of p,if the numbers x, 2x+p and 3x+6 are three consecutive terms of an a.p
Answers
Answered by
Praphul
Since it is APthe difference of 3x+6 and 2x+p is equal to the difference of 2x+p and x
So 3x+6 -(2x+ p)= 2x+p-x
3 x+6-2x-p= x+ p
X+6-p= x+p
Canceling x on both sides and bringing ps to one side we will have 2p= 6
P=3
So 3x+6 -(2x+ p)= 2x+p-x
3 x+6-2x-p= x+ p
X+6-p= x+p
Canceling x on both sides and bringing ps to one side we will have 2p= 6
P=3
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