Ask a New Question

Question

A roller coaster car is moving at 20.0m/s along a straight horizontal track. what is the speed after climbing a 15.0m hill? neglect the effects of friction
12 years ago

Answers

drwls
The kinetic energy loss will equal the potential energy gain.
V1^2/2 - V2^2/2 = g H = 147 m^2/s^2
V1^2/2 = 200 m^2/s^2
V2^2 = 2*(200 - 147) = 106 m^2/s^2
V2 = 12.1 m/s
12 years ago

Related Questions

A roller coaster is moving at 10 m/s at the top of a hill and 22 m/s at the bottom of the hill two s... A roller-coaster car is moving at 20.0 m/s along a straight horizontal track. What is its speed af... A 650 kg roller coaster car has two points of reference given to an observer. Point A, at a height o... A roller coaster car is at the top of a 4.0 x 10 m hill, above the ground. It starts from rest. It t... A roller coaster will only run with a certain number of people on board. The graph below represents... A roller coaster is at the top of a 54 meter hill. The car and it’s passengers have a total mass of... A roller coaster is moving at 25m / s at the bottom of a hill. Three seconds later it reaches the to... Roller Coaster Ride Roller coasters can be categorized by the height of the first hill. Assume the...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use