Question

A boat is tied to a pier with a 25-foot rope so that the distance between the top of the pier and the top of the boat deck is 7 feet. If the water level hoes down 8 feet with the low tide , how much closer ( in feet) is the boat to the base of the pier? Assume the rope is always taut? Shows your work

Answer 1

high tide:
x^2 + 7^2 = 25^2
x^2 = 576
x = 24

low tide:
x^2 + 15^2 = 25^
x^2 = 400
x = 20

The distance change is 4 ft