Asked by Renee
Two billard balls move toward one another.The balls have identical masses, and the collision is perfectly elastic. The initial velocity of the balls are +30 cm/s and -20 cm/s, what is the velocity of each ball after the collision?
Answers
Answered by
Jennifer
Use conservation of momentum, and conservation of kinetic energy for an elastic collision.
m*30 + m*-20 = m*v1 + m*v2
where v1 is the final speed of the first ball, v2 is the final speed of the second ball
Simplifying the equation (dividing both sides by m, adding like terms)
10 = v1 + v2
Conservation of kinetic energy:
1/2*m*30^2 +1/2*m*(-20)^2 = 1/2*m*v1^2 + 1/2 *m*v2^2
or
90 + 40 = 130 = v1^2 + v2^2
You have two equations with two unknowns:
10 = v1 + v2
130 = v1^2 + v2^2
Use algebra to solve for v1 and v2
m*30 + m*-20 = m*v1 + m*v2
where v1 is the final speed of the first ball, v2 is the final speed of the second ball
Simplifying the equation (dividing both sides by m, adding like terms)
10 = v1 + v2
Conservation of kinetic energy:
1/2*m*30^2 +1/2*m*(-20)^2 = 1/2*m*v1^2 + 1/2 *m*v2^2
or
90 + 40 = 130 = v1^2 + v2^2
You have two equations with two unknowns:
10 = v1 + v2
130 = v1^2 + v2^2
Use algebra to solve for v1 and v2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.