Asked by hawi
What is the pH of a solution when 1ml of 0.10M NaOH is added to 100ml of buffer containing 0.1M acetic acid and 0.1M sodium acetate?
Answers
Answered by
DrBob222
100 mL x 0.1M HAc = 10 mmoles.
100 mL x 0.1M NaAc = 10 mmols.
1 mL x 0.1M NaOH = 0.1 mmol.
-----------------------
......HAc + OH^- ==> Ac^- + H2O
I.....10.....0.......10
add........0.1..............
C...-0.1..-0.1.......+0.1
E.....9.9...0........10.1
Substitute the equilibrium values into the Henderson-Hasselbalch equation and solve for pH.
100 mL x 0.1M NaAc = 10 mmols.
1 mL x 0.1M NaOH = 0.1 mmol.
-----------------------
......HAc + OH^- ==> Ac^- + H2O
I.....10.....0.......10
add........0.1..............
C...-0.1..-0.1.......+0.1
E.....9.9...0........10.1
Substitute the equilibrium values into the Henderson-Hasselbalch equation and solve for pH.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.