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z = 1+i
r = √(1+1) = √2
tanØ = 1/1 = 1
Ø = 45°
1+i = √2(cos 45° + i sin45°)
what is the trigonometric form of z=1+i?
3 answers
what is z= -2-2square root of 3i in trigonometric form.
z= -2 - 2√3
r = √(4 + 12) = √16 or 4
tan Ø = -2√3/-2 , Ø must be in III
Ø = 240°
-2 - 2√3 i = 4(cos 240° + i sin 240°)
checking:
4(cos 240° + i sin 240°)
= 4(-.5 - √3/2)
= -2 - 2√3
r = √(4 + 12) = √16 or 4
tan Ø = -2√3/-2 , Ø must be in III
Ø = 240°
-2 - 2√3 i = 4(cos 240° + i sin 240°)
checking:
4(cos 240° + i sin 240°)
= 4(-.5 - √3/2)
= -2 - 2√3