Question
Given 120mL of neon gas at 40 degrees C, what teperature corresponds to a volume that has been decreased by 30mL?
(P1V2)/T1 = (P2V2)/T2.
Use V1 = 120 mL and V2 = 120-30=90 mL
Don't forget to change degrees C to Kelvin.
Kelvin = 273 + <sup>o</sup>C.
(P1V2)/T1 = (P2V2)/T2.
Use V1 = 120 mL and V2 = 120-30=90 mL
Don't forget to change degrees C to Kelvin.
Kelvin = 273 + <sup>o</sup>C.