Asked by Lindsay
A fish tank is 50 cm long, 34 cm wide and 24 cm high. It contains water to depth of 18 cm. Four identical spheres are placed in the tank and are fully submerged. The water level rises by 4.5 cm.
1.What is the volume before the spheres were added?
2. What is the volume of each sphere?
3. What is the radius of the spheres?
1.What is the volume before the spheres were added?
2. What is the volume of each sphere?
3. What is the radius of the spheres?
Answers
Answered by
Reiny
Archimedes would have done it this way
original volume
= 50x34x18
=30600
change in volume
= 50x34x4.5
= 7650
---- caused by the two spheres
so each sphere had a volume of 3825 cm^3
V of sphere = (4/3)πr^3
(4/3)πr^3 = 3825
r^3 = 913.151..
r = cuberoot(913.151...) = appr 9.70 cm
original volume
= 50x34x18
=30600
change in volume
= 50x34x4.5
= 7650
---- caused by the two spheres
so each sphere had a volume of 3825 cm^3
V of sphere = (4/3)πr^3
(4/3)πr^3 = 3825
r^3 = 913.151..
r = cuberoot(913.151...) = appr 9.70 cm
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