calculate the amount of energy required to convert 55.0g of ice at -10.0°c into steam at 125°c?

Answer 1

Two formulas you need.
Within a phase:
mass x specific heat x (Tfinal-Tinitial). For example: water from zero C to 100 C as a liquid it will be
grams H2O x 4.184 x (100-0) = q

At a phase change:
melting point phase change is
q = mass ice x heat fusion.

boiling point phase change is
q = mass water x heat vaporization.

Then all all of the qs together.

Answer 2

169713.5 joules or 40562.5 calories

Answer 3

169,713.5 joules or 40562.5 calories