A golfer is enjoying a day out on the links. What maximum height will a 323.5 m drive reach if it is launched at an angle of 21.0◦ to the ground? The acceleration due to gravity is 9.81 m/s^2. Answer in units of m

Answer 1

Range = Vo^2*sin(2A)/g = 323.5 m.
Vo^2*sin(42)/9.8 = 323.5
Vo^2*0.06828 = 323.5
Vo^2 = 4737.94

Vo = 68.8m/s @ 21o.
Yo = 68.8*sin21 = 24.67 m/s = Ver. comp.

h = (Y^2-Yo^2)/2g.
h = (0-608.48)-19.6 = 31.0 m.

Answer 2

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