Question
An automatic drier spins wet clothes at an angular speed of 4.8 rad/s. Starting from rest, the drier reaches its operating speed with an average angular acceleration of 3.6 rad/s2. How long does it take the drier to come up to speed?
Answers
Gince Mungs
someone confirm this;
a)ω =(65rev/min)*1min/60sec*2πrads/1rev=65 π rads/30sec b) ω0=0 c) α=7rad/s^2
Hence, t= (ω- ω0)/α
a)ω =(65rev/min)*1min/60sec*2πrads/1rev=65 π rads/30sec b) ω0=0 c) α=7rad/s^2
Hence, t= (ω- ω0)/α