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what is the pH of a 0.10 M solution of methylamine (CH3NH2, kb= 4.4*10^-4) at 25 degree C?

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Let's call CH3NH2 simply BNH2.
...........BNH2 + HOH ==> BNH3^+ + OH^-
I..........0.10............0........0
C............-x............x........x
E.........-0.10-x...........x........x

Substitute the E line in the Kb expression and solve for OH^-, then convert this to pH.
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