Asked by lee
Could someone please explain the steps in finding all the real zeroes
y=(x-12)^3-7
I do not know how
y=(x-12)^3-7
I do not know how
Answers
Answered by
Anonymous
you want
(x-12)^3 - 7 = 0
(x-12)^3 = 7
x-12 = ∛7
x = 12 + ∛7
(x-12)^3 - 7 = 0
(x-12)^3 = 7
x-12 = ∛7
x = 12 + ∛7
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