Asked by kym
find the 6 trigonometric functions of tan (-3/8): sin < Ø
Answers
Answered by
Steve
If you want good answers, post good questions. If you meant
find the 6 trigonometric functions of θ, where tanθ = -3/8 and θ < π
then, knowing that the hypotenuse is √(3^2+8^2) = √73,
sinθ = 8/√73
cosθ = -3/√73
. . .
find the 6 trigonometric functions of θ, where tanθ = -3/8 and θ < π
then, knowing that the hypotenuse is √(3^2+8^2) = √73,
sinθ = 8/√73
cosθ = -3/√73
. . .
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