Asked by Disha
the height in feet of a rocket from ground level is given by the function f(t)= -16t^2+160t. what is the instantaneous velocity of the rocket 3 seconds after it is launched?
A 32 feet/sec
B 64 feet/sec
C 12 feet/sec
D 10 feet/sec
E 8 feet/sec
A 32 feet/sec
B 64 feet/sec
C 12 feet/sec
D 10 feet/sec
E 8 feet/sec
Answers
Answered by
Steve
okay - another power example. What do you get?
Answered by
Disha
do i plug 3 in for t?
Answered by
Steve
first take the derivative, which is the velocity at any instant.
ds/dt = ft/s, or velocity
Plug 3 into that.
ds/dt = ft/s, or velocity
Plug 3 into that.
Answered by
jessica
its going to be 32 hun
Answered by
Steve
Hmm. How did you get that, jessica?
f'(t) = -32t + 160
f'(3) = -96 + 160 = 64
f'(t) = -32t + 160
f'(3) = -96 + 160 = 64
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