Asked by Erica
A rocket is launched from ground level with an initial vertical velocity (v0) of 176 ft/s. After how many seconds will the rocket hit the ground? (Hint: h(t) = -16t2 + v0t + h0)
Answers
Answered by
Steve
h(t) = 176t - 16t^2
it hits the ground when h=0
176t-16t^2 = 0
16t(11-t) = 0
t=11
it hits the ground when h=0
176t-16t^2 = 0
16t(11-t) = 0
t=11
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