Asked by Katarzyna
Chris has a chance of making par on each hole that he plays. Today he plans on playing only four holes. Find probability of each event. A) he makes par on at least one hole. B) he makes par on the first two holes and the fourth hole.
Answers
Answered by
bobpursley
What chance? Lets say the probablility is N
a. Probab(at least one hole)=1-prob(notany)=1-(1-A)^4
b. Pr(first two, and fourth)=A*A*(1-A)*A
a. Probab(at least one hole)=1-prob(notany)=1-(1-A)^4
b. Pr(first two, and fourth)=A*A*(1-A)*A
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