Question

One mole of an ideal gas initially at a temperature of Ti = 7.4°C undergoes an expansion at a constant pressure of 1.00 atm to eight times its original volume.
(a) Calculate the new temperature Tf of the gas.______J


(b) Calculate the work done on the gas during the expansion.________kJ

Answer 1

(a)
Ti=273+7.4=280.4 K
Vi/Ti = Vf/Tf
Vi/280.4 =8 Vi/Tf
Tf=8•280.4 = 2243.2 K
b) p•ΔV=νRΔT
ν =1 mol
p•ΔV= RΔT
W = p•ΔV= RΔT=
= 8.31•(2243.2-280.4)=
=1.63•10⁴ J =16.3 kJ

Answer 2

Waw..Elena answer is so brilliant..
Thank you so much..
Hope can know you well

Answer 3

Good response, just remember to have a negative sign in the work if asking for work done on the gas.