Question
One mole of an ideal gas initially at a temperature of Ti = 7.4°C undergoes an expansion at a constant pressure of 1.00 atm to eight times its original volume.
(a) Calculate the new temperature Tf of the gas.______J
(b) Calculate the work done on the gas during the expansion.________kJ
(a) Calculate the new temperature Tf of the gas.______J
(b) Calculate the work done on the gas during the expansion.________kJ
Answers
Elena
(a)
Ti=273+7.4=280.4 K
Vi/Ti = Vf/Tf
Vi/280.4 =8 Vi/Tf
Tf=8•280.4 = 2243.2 K
b) p•ΔV=νRΔT
ν =1 mol
p•ΔV= RΔT
W = p•ΔV= RΔT=
= 8.31•(2243.2-280.4)=
=1.63•10⁴ J =16.3 kJ
Ti=273+7.4=280.4 K
Vi/Ti = Vf/Tf
Vi/280.4 =8 Vi/Tf
Tf=8•280.4 = 2243.2 K
b) p•ΔV=νRΔT
ν =1 mol
p•ΔV= RΔT
W = p•ΔV= RΔT=
= 8.31•(2243.2-280.4)=
=1.63•10⁴ J =16.3 kJ
Ewin
Waw..Elena answer is so brilliant..
Thank you so much..
Hope can know you well
Thank you so much..
Hope can know you well
Hunter
Good response, just remember to have a negative sign in the work if asking for work done on the gas.