Asked by Hussen
An antitank weapon fires a 3.0 kg rocket which acquires a speed of 50. m/s after traveling 90. cm down a launching tube. Assuming the rocket was accelerated uniformly, what force acted on it?
Answers
Answered by
Henry
a = (V^2-Vo^2)/2d.
a = (2500-0)/1.8m = 1389 m/s^2.
F = m*a = 3 * 1389 = 4167 N.
a = (2500-0)/1.8m = 1389 m/s^2.
F = m*a = 3 * 1389 = 4167 N.
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