What is the pH of a 0.350M HBrO Solution? HBrO, Ka=2.3 x 10^-9

Answer 1

........HBrO ==> H^+ + BrO^-
I.......0.350M....0......0
C..........-x.....x......x
E......0.350-x.....x.....x

Substitute the E line into the Ka expression and solve for H^+. Then pH = log(HT^+)