Asked by chris neives

Two 0.61 kg basketballs, each with a radius of 13 cm, are just touching. How much energy is required to change the separation between the centers of the basketballs to the following (a)1 meter
(b) 10 meters

Answers

Answered by Elena
the gravitational constant G =6.67•10⁻¹¹ N•m²/kg²,
PE₁=G•m₁•m₂/R₁
PE₂=G•m₁•m₂/R₂
E=ΔPE= PE₁-PE₂=
=G•m₁•m₂/R₁-G•m₁•m₂/R₂=
=G•m₁•m₂(1/ R₁- 1/R₂)= …
R₁=0.26 m
R₂= 1 m, 10 m
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