Asked by stoic-rider77
Turning a doorknob through 0.53 of a revolution requires 0.10 J of work. What is the torque required to turn the doorknob?
Answers
Answered by
drwls
(Average Torque) x (Angle in radians) = Work
Torque = 0.1/(2*pi*0.53) = ___ J
Torque = 0.1/(2*pi*0.53) = ___ J
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