A box have a mass of 50 Kilograms is dragged across a horizontal floor by means of a rope tied on the front of it. The

coefficient of friction between the box and the floor is .3. If the angle between the rope and the floor is 30 degrees, what
force must be exerted on the rope to move the box at a constant speed? (

2 answers

upward force on box: P*sin30=P/1
horizontal force: P cos30

at constant speed,

pulling force=friction force
Pcos30=mu(mg-P/2)
solve for P
Please help to answer this question