125 C = 398 K
molar mass of CCl4 = 12 + 4*35.5 = 154 g/mol
22.4 liters of an ideal gas contains 1 mole at STP, or 0.975*(273/398) = 0.6688 moles at 0.975 atm and 398 K.
density of CCl4 = 0.6688*154 g/(22.4 l)
= 4.60 g/l
You could also calculate moles per volume using
n/V = P/RT
and multiply that by the molar mass.
what is the density of carbon tetrachloride vapor at 0.975 atm and 125 celsius
1 answer