what is the heat capacity of iron when a 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and it's temperature changes from 25 degrees celcius to 175 degrees celcius

1086.75J/[15.75g*150C] = 0.460 J/(g*C)

To find the heat capacity of iron, we can use the formula:

Q = m × C × ΔT

Where:
Q is the heat energy absorbed (in joules),
m is the mass of the iron (in grams),
C is the specific heat capacity of iron (in J/g°C), and
ΔT is the change in temperature (in °C).

Given:
m = 15.75 g
Q = 1086.75 J
ΔT = 175°C - 25°C = 150°C

Substituting these values into the formula, we can solve for C:

1086.75 J = 15.75 g × C × 150°C

Dividing both sides of the equation by (15.75 g × 150°C):

C = 1086.75 J / (15.75 g × 150°C)

C ≈ 0.483 J/g°C

Therefore, the heat capacity of iron is approximately 0.483 J/g°C.

To find the heat capacity of iron, we can use the formula:

Heat Capacity = (Heat Energy Absorbed) / (Change in Temperature)

Given:
Mass of iron (m) = 15.75 g
Heat energy absorbed (Q) = 1086.75 J
Initial temperature (T1) = 25 °C
Final temperature (T2) = 175 °C

First, we need to convert the mass of iron from grams to kilograms:
Mass of iron (m) = 15.75 g = 0.01575 kg

Next, we calculate the change in temperature:
Change in temperature = Final temperature - Initial temperature = (175 °C - 25 °C) = 150 °C

Now, we can substitute these values into the formula to find the heat capacity:
Heat Capacity = (1086.75 J) / (150 °C)

Hence, the heat capacity of the iron is 7.245 J/°C (rounded to three decimal places).