Question
For the lewis structure of BCl3, does it have a total of 24 valence electrons? Also does it have a total of 4 bonds? If possible can you draw the lewis structure?
Answers
Yes it has 24 electrons. It can't have but three bonds since there are only three atoms hooked to it (the three Cl atoms). I can't draw the Lewis dot structure on this forum but here is a site that shows it. Frankly I don't like the way this site does it but the structure is correct.
But when I take the total number of electrons needed to be "happy" subract the total number of valence electron the result is 4 bonds.
1*8=8
3*8=24
24+8=32
1*3=3 valence electrons
3*7=21 valence electrons
Total valence electron: 24
so... 32-24=8/2=4
1*8=8
3*8=24
24+8=32
1*3=3 valence electrons
3*7=21 valence electrons
Total valence electron: 24
so... 32-24=8/2=4
By the way, is that correct??
B doesn't obey the octet rule. Look at that structure again at the site and you will see B has only 6 electrons while each Cl has 8.
There can be only three bonds for obvious reasons even if B obeyed the octet rule. That's because there are only three Cl atoms; what else would you add to make the fourth bond?
So would N2 have two bonds then?
I don't think you posted the site.
Excuse me! Here is the site. Sorry about that.
http://biochemhelp.com/lewis-structure-for-bcl3.html
As for nitrogen, it has 10 electrons; the Lewis dot structure is <b>:N:::N:</b>
http://biochemhelp.com/lewis-structure-for-bcl3.html
As for nitrogen, it has 10 electrons; the Lewis dot structure is <b>:N:::N:</b>
So for N2, it would be like this?
Step1: 5*2=10 valence electrons
Step2: 8*2=16 electrons total
Step3: 16-10=6 electrons
Step4: 6/2= 3 bond pairs
Step5: 10-6=4/2=2 lone pairs
I am confident that this is correct! Please check.
Step1: 5*2=10 valence electrons
Step2: 8*2=16 electrons total
Step3: 16-10=6 electrons
Step4: 6/2= 3 bond pairs
Step5: 10-6=4/2=2 lone pairs
I am confident that this is correct! Please check.
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