Asked by Q
A refrigerator does 18kJ of work while moving 115 kJ of thermal enegy from inside the refrigerator. What is its coefficient of performance?
Answers
Answered by
drwls
Refrigerators do not do work. Work has to be done UPON them to transfer heat out. I will assume that they meant to say 18 kJ of work IS CONSUMED by the refrigerator.
Refrigerator C.O.P. = Qout/Win
= 115/18 = 6.38
Refrigerator C.O.P. = Qout/Win
= 115/18 = 6.38
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.