Asked by jazz
the paralle side of trapezium are 20m and 30m and its non-paralle sides are 6m and 8m .find the area of trapezium
Answers
Answered by
Steve
draw a diagram. There will be two triangles at the ends, aid since 20=30-10, their bases will add up to 10.
If the triangle with hypotenuse 6 has base x, then the height h of the trapezoid is
h^2 = 6^2 - x^2
h^2 = 8^2 - (10-x)^2
so,
36 - x^2 = 64 - (10-x)^2
36-x^2 = 64 - 100 + 20x - x^2
72 = 20x
x = 18/5
h^2 = 36 - (18/5)^2
h = 24/5
area = (20+30)/2 * 24/5 = 120
If the triangle with hypotenuse 6 has base x, then the height h of the trapezoid is
h^2 = 6^2 - x^2
h^2 = 8^2 - (10-x)^2
so,
36 - x^2 = 64 - (10-x)^2
36-x^2 = 64 - 100 + 20x - x^2
72 = 20x
x = 18/5
h^2 = 36 - (18/5)^2
h = 24/5
area = (20+30)/2 * 24/5 = 120
Answered by
shubham raj
120m
Answered by
shubham raj
120m^2
Answered by
Rohit
Answer is too hard
Answered by
Hannah
This answers is not cleared my doubt
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