57 g total
12/57 and 45/57 fractions.
Zn(NO3)2_____________
H2O _____________
12/57 and 45/57 fractions.
First, let's find the mass of zinc nitrate, Zn(NO3)2:
12.0 g (mass of Zn(NO3)2)
Next, let's find the mass of water, H2O:
45.0 g (mass of water)
Now, let's calculate the percent composition by weight of each component:
Percent composition of Zn(NO3)2:
= (mass of Zn(NO3)2 / total mass of solution) * 100
= (12.0 g / (12.0 g + 45.0 g)) * 100
= (12.0 g / 57.0 g) * 100
≈ 21.05%
Percent composition of H2O:
= (mass of H2O / total mass of solution) * 100
= (45.0 g / (12.0 g + 45.0 g)) * 100
= (45.0 g / 57.0 g) * 100
≈ 78.95%
Therefore, the percent composition by weight of the solution is approximately:
Zn(NO3)2: 21.05%
H2O: 78.95%
First, let's calculate the mass of each component:
1. Zn(NO3)2 (Zinc Nitrate):
Given that the mass of zinc nitrate is 12.0 g.
2. H2O (Water):
Given that the mass of water is 45.0 g.
Next, we can calculate the total mass of the solution:
Total mass = mass of Zn(NO3)2 + mass of H2O
Total mass = 12.0 g + 45.0 g
Now we can calculate the percent composition by weight:
Percent composition of Zn(NO3)2 = (mass of Zn(NO3)2 / total mass) * 100
Percent composition of Zn(NO3)2 = (12.0 g / (12.0 g + 45.0 g)) * 100
Percent composition of Zn(NO3)2 = (12.0 g / 57.0 g) * 100
Finally, we can calculate the percent composition of water:
Percent composition of H2O = (mass of H2O / total mass) * 100
Percent composition of H2O = (45.0 g / (12.0 g + 45.0 g)) * 100
Percent composition of H2O = (45.0 g / 57.0 g) * 100
Therefore, the percent composition by weight of the solution is:
Zn(NO3)2: (12.0 g / 57.0 g) * 100 = 21.05%
H2O: (45.0 g / 57.0 g) * 100 = 78.95%
So, the percent composition by weight of the solution is approximately:
Zn(NO3)2: 21.05%
H2O: 78.95%