Question

Sulfuric acid reacts with sodium hydroxide according to this equation:

H2S04 + 2 NaOH Na2(SO4) + 2 H2O

A 10.00 mL sample of the H2SO4 solution required 13.71 mL of 0.309 M NaOH for neutralization. Calculate the molarity of the acid.



0.01371L * 0.309 mol/L = 0.004236 mol NaOH

so, you need half that many moles of H2SO4, or 0.002118 mol H2SO4

0.002118 mol / 0.01L = 0.2118 M H2SO4

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