Asked by Samuel
A person pulls a crate with 120 N of force against 100 N of friction a distance of 5 meters. Find the energy the person expends pulling the crate, the amount of energy converted to heat via friction, and the increase in the kinetic energy of the crate.
Answers
Answered by
Elena
W=Fs=120•5 = 600 J
W(fr)=100•5=500 J
ΔKE=(120-100)•5=100J
W(fr)=100•5=500 J
ΔKE=(120-100)•5=100J
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