Question
A person pulls a crate with 120 N of force against 100 N of friction a distance of 5 meters. Find the energy the person expends pulling the crate, the amount of energy converted to heat via friction, and the increase in the kinetic energy of the crate.
Answers
Elena
W=Fs=120•5 = 600 J
W(fr)=100•5=500 J
ΔKE=(120-100)•5=100J
W(fr)=100•5=500 J
ΔKE=(120-100)•5=100J