Asked by Mikey
If an objects vbr is 6.32N/sc what is its mass? I'm so stuck...:((((
Answers
Answered by
PhysicsPro
Solve:
vbr{lr<5vvx><f(nn)/.bbn>
vbr<lr><5.12>(9.8)^3
.bbn=%ff
%ff=F(9x)
.bbn=%ff9x
.bbn=.133%tri
.bbn=.tri
t.ri=vbr
v=161.2
b=39.1
r=12.7
mass=.66kg
Remember the .bbn is equal to the percent factor of the function by 9x or inversely with y9.
vbr{lr<5vvx><f(nn)/.bbn>
vbr<lr><5.12>(9.8)^3
.bbn=%ff
%ff=F(9x)
.bbn=%ff9x
.bbn=.133%tri
.bbn=.tri
t.ri=vbr
v=161.2
b=39.1
r=12.7
mass=.66kg
Remember the .bbn is equal to the percent factor of the function by 9x or inversely with y9.
Answered by
Mikey
Thank you!!! Why is t.ri = vbr and not just tri?
Answered by
PhysicsPro
Factor out .bbn and vbr and solve with tri the decimal place is moved one.
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