vbr{lr<5vvx><f(nn)/.bbn>
vbr<lr><5.12>(9.8)^3
.bbn=%ff
%ff=F(9x)
.bbn=%ff9x
.bbn=.133%tri
.bbn=.tri
t.ri=vbr
v=161.2
b=39.1
r=12.7
Sub in values of vbr
For y(x)=ln(3+x2), find y(6)
2 answers
y(6) = ln(3+36) = ln 39 or appr 3.66356