how do you find x in 7-=log(x/10^-12)

Question

Reiny · Answer

I will assume that -= is a typo and should be just = 7 = log(x/10^-12) 7 = logx - log 10^-12 7 = logx - (-12) 7-12= logx -5 = logx x = 10^-5

Rebekah · Answer

the thing is its / instead of - so I thought that I multiply each side by 10^-12 but im not sure

Steve · Answer

you cannot multiply by 10^12 because that is inside the log.

suppose you had 2 = √(x/4)
You can't multiply by 4, giving
8 = √x
because that would be trying to slide a value through the "walls" of the function calculation