Asked by evelyn
a 12.0g of sample A (70.2g/mol)was burned in a bomb calorimeter in an excess of O2(g).
A+2 O2(g)---> 2 CO2(g) +2 H2O(l)
The temperature of the calorimeter rose from 25.00 degrees celisus to 29.82 degree celisus. ifthe heat capacity of the calorimeter and its contents is 13.43kJ/degree celisus, what is the heat of change for the reaction?
A+2 O2(g)---> 2 CO2(g) +2 H2O(l)
The temperature of the calorimeter rose from 25.00 degrees celisus to 29.82 degree celisus. ifthe heat capacity of the calorimeter and its contents is 13.43kJ/degree celisus, what is the heat of change for the reaction?
Answers
Answered by
DrBob222
q = heat of rxn = [Ccal x (Tfinal-Tintial)]
Then q/12.0 g = delta H/gram. Convert to kJ/mol by (dH/gram)*70.2 = ?
Then q/12.0 g = delta H/gram. Convert to kJ/mol by (dH/gram)*70.2 = ?
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