Asked by Lux
A ball is dropped from a height of 36 feet. The quadratic equation
d=1/2 gt^2
is used to calculate the distance (d) the ball has fallen after t seconds. The constant g is the acceleration of gravity, 9.8m/s^2. How long does it take the ball to hit the ground?
A ball in problem 2 is dropped again, from a different height. This time, it takes 3 seconds to hit the ground. How far does it fall?
d=1/2 gt^2
is used to calculate the distance (d) the ball has fallen after t seconds. The constant g is the acceleration of gravity, 9.8m/s^2. How long does it take the ball to hit the ground?
A ball in problem 2 is dropped again, from a different height. This time, it takes 3 seconds to hit the ground. How far does it fall?
Answers
Answered by
mathtaculator
for 1.
d= 36 ft
g = 9.8
find t.
t=?
plug it in and find the answer
for 2.
t=3
g=9.8
find d
d=?
d= 36 ft
g = 9.8
find t.
t=?
plug it in and find the answer
for 2.
t=3
g=9.8
find d
d=?
Answered by
Anonymous
ball is dropped from a height of 36 feet. The quadratic equation
d=1/2 gt^2
is used to calculate the distance (d) the ball has fallen after t seconds. The constant g is the acceleration of gravity, 9.8m/s^2. How long does it take the ball to hit the ground?
A ball in problem 2 is dropped again, from a different height. This time, it takes 3 seconds to hit the ground. How far does it fall?
d=1/2 gt^2
is used to calculate the distance (d) the ball has fallen after t seconds. The constant g is the acceleration of gravity, 9.8m/s^2. How long does it take the ball to hit the ground?
A ball in problem 2 is dropped again, from a different height. This time, it takes 3 seconds to hit the ground. How far does it fall?
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