Asked by emani

solve ;2 xsquare y-3 xsquare+4 y=2010
Answered by Steve
2x^2y - 3x^2 + 4y = 2010
y(2x^2+4) = 2010 + 3x^2
y = (2010+3x^2)/(2x^2+4)
= 3/2 + 1002/(x^2+2)

now what?
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