Asked by Maria
Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2x-cos2x
ive tried this problem so many times I need help with it...
ive tried this problem so many times I need help with it...
Answers
Answered by
Reiny
I believe you mean
(1+sin2x + cos2x)/(1+sin2x - cos2x)
= (sin^2 x + cos^2 x + 2sinxcosx + cos^2 x - sin^2x)/(sin^2 x + cos^2 x + 2sinxcosx - cos^2x + sin^2x)
= (2cos^2 x + 2sinxcosx)/(2sin^2 x + 2sinxcosx)
= 2cosx(cosx+sinx)/((2sinx(sinx+cos))
= 2cosx/2sinx
= cot x
(1+sin2x + cos2x)/(1+sin2x - cos2x)
= (sin^2 x + cos^2 x + 2sinxcosx + cos^2 x - sin^2x)/(sin^2 x + cos^2 x + 2sinxcosx - cos^2x + sin^2x)
= (2cos^2 x + 2sinxcosx)/(2sin^2 x + 2sinxcosx)
= 2cosx(cosx+sinx)/((2sinx(sinx+cos))
= 2cosx/2sinx
= cot x
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.