Asked by Anonymous
Use the following numbers for this question.
MEarth 5.98e+24 kg
MJupiter 1.9e+27 kg
MSun 2e+30 kg
Earth-Sun distance 150000000000 m
Jupiter-Sun distance 778000000000 m
rE 6380000 m
rJ 69000000 m
G = 6.67e-11 Nm2kg-2
the acceleration due to gravity at the surface of Jupiter has been found to be 26.6 m/s^2
How fast would a steel sphere be going if you let it drop 20 m from rest, near the surface of Jupiter?
How many Earth years does it take Jupiter to orbit the Sun once, assuming a circular orbit and one Earth year as 365.25 days?
What is the force of gravity that the sun exerts on the Earth?
The sun pulls on the Earth with a huge amount of force. Why does the Earth not fall into the Sun? Explain
MEarth 5.98e+24 kg
MJupiter 1.9e+27 kg
MSun 2e+30 kg
Earth-Sun distance 150000000000 m
Jupiter-Sun distance 778000000000 m
rE 6380000 m
rJ 69000000 m
G = 6.67e-11 Nm2kg-2
the acceleration due to gravity at the surface of Jupiter has been found to be 26.6 m/s^2
How fast would a steel sphere be going if you let it drop 20 m from rest, near the surface of Jupiter?
How many Earth years does it take Jupiter to orbit the Sun once, assuming a circular orbit and one Earth year as 365.25 days?
What is the force of gravity that the sun exerts on the Earth?
The sun pulls on the Earth with a huge amount of force. Why does the Earth not fall into the Sun? Explain
Answers
Answered by
Anonymous
never mind on the last parts, just what is the answer to this question using those numbers
How fast would a steel sphere be going if you let it drop 20 m from rest, near the surface of Jupiter?
How fast would a steel sphere be going if you let it drop 20 m from rest, near the surface of Jupiter?
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