Asked by MATTHEW GOWOK POLIT
1. A body of mass 400g dropped from a height of 30m. If after rebounce the ball loses 2/3 of its energy, calculate: <a>.the velocity before bounce, <b>.the height after rebounce, <c>.the velocity after rebounce</b>
Answers
Answered by
Henry
a. V^2 = Vo^2 + 2g*d.
V^2 = 0 + 19.6*30 = 588
V = 24.2 m/s.
V^2 = 0 + 19.6*30 = 588
V = 24.2 m/s.
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